document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885577>Question 885577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a triangle is 30 and the lengths are x+3,2x and 4x-1 find the length of each side<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535244 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So to find the perimeter of a figure you need to add up all the side lengths.  So we will add up x+2, 2x, and 4x-1 and set it equal to 30(the given perimeter).  <br>\r<BR>\n" );
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document.write( "x+2+2x+4x-1 = 30 moving like terms together<BR>\n" );
document.write( "x+2x+4x+2-1 = 30 combining like terms<BR>\n" );
document.write( "7x+1 = 30 Subtracting 1 from both sides<BR>\n" );
document.write( "6x = 29 Dividing both sides by 6<BR>\n" );
document.write( "x = 29/6<br>\r<BR>\n" );
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document.write( "Now we plug x into the given expressions for the side lengths and simplify.<br>\r<BR>\n" );
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document.write( "Side 1 = x+3 = 29/6 +3 = (29+18)/6 = 47/6<BR>\n" );
document.write( "Side 2 = 2x = 2(29/6) = 29/3<BR>\n" );
document.write( "Side 3 = 4x-1 = 4(29/6)-1 = 58/3 -1 = 55/3 </SPAN>\n" );
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