document.write( "Question 885577: If the perimeter of a triangle is 30 and the lengths are x+3,2x and 4x-1 find the length of each side
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Algebra.Com's Answer #535242 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Perimeter of Triangle:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter = (Side1) + (Side2) + (Side3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30 = (x+3) + (2x) + (4x-1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30 = x+3 + 2x + 4x-1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30 = 7x+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30-2 = 7x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "28 = 7x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7x = 28\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 28/7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use this to find the length of each side\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side1: x+3 = 4+3 = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side2: 2x = 2*4 = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side3: 4x-1 = 4*4-1 = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The three sides are: 7, 8, 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: 7+8+15 = 15+15 = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the answer checks out. \n" ); document.write( " |