document.write( "Question 885468: please help me to solve this equation; 2x^2-x<0 \n" ); document.write( "
Algebra.Com's Answer #535217 by Theo(13342)\"\" \"About 
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set the equation equal to 0 and solve for x.
\n" ); document.write( "you get:
\n" ); document.write( "2x^2 - x = 0
\n" ); document.write( "factor out an x to get:
\n" ); document.write( "x * (2x - 1) = 0
\n" ); document.write( "x will be equal to 0 or x will be equal to 1/2.
\n" ); document.write( "evaluate the equation when x is less than 0.
\n" ); document.write( "you will find that 2x^2 - x is positive.
\n" ); document.write( "evaluate the equation when x is greater than 1/2.
\n" ); document.write( "you will find that 2x^2 - x is positive.
\n" ); document.write( "evaluate the equation when x is greater than 0 and less than 1/2.
\n" ); document.write( "you will find that 2x^2 - x is negative.
\n" ); document.write( "the expression os 2x^2 - x is less than 0 when x is greater than 0 and less than 1/2.
\n" ); document.write( "a grph of your equation is shown below:
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