document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74492>Question 74492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a northbound train left the station at noon. 2 hours later a southbound train left the same station. At 6 the 2 trains were 450 miles apart. Find the rate of the 2 trains if the northbound train was traveling 25 mph faster than the southbound train </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53518 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 450=6(x+25)+4x<BR>\n" );
document.write( "450=6x+150+4x<BR>\n" );
document.write( "10x=450-150<BR>\n" );
document.write( "10x=300<BR>\n" );
document.write( "x=300/10<BR>\n" );
document.write( "x=30 mph for the southbound train & 30+25=55 mph for the northbound train<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "450=6*55+4*30<BR>\n" );
document.write( "450=330+120<BR>\n" );
document.write( "450=450 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );