document.write( "Question 885409: I need help solving : 5-√x+7 = √x-8
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document.write( "(both x+7 and x-8 are both in the square root)\r
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document.write( "The answer choices provided are:
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document.write( "A) {8,-7} B) 0 C) {9} D) {2}\r
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document.write( "Also, could you please explain how the get the correct answer?\r
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document.write( "Thanks. \n" );
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Algebra.Com's Answer #535157 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 5 -square root(x+7) = square root(x-8) \n" ); document.write( "5 = square root(x-8) + square root(x+7) \n" ); document.write( "square both sides of = \n" ); document.write( "25 = (x-8) +2square root(x-8)square root(x-7) +(x+7) \n" ); document.write( "25 = 2x +2square root(x-8)square root(x-7) -1 \n" ); document.write( "add 1 to both sides of = \n" ); document.write( "26 = 2x +2square root(x-8)square root(x-7) \n" ); document.write( "divide both sides of = by 2 \n" ); document.write( "13 = x +square root(x-8)square root(x-7) \n" ); document.write( "subtract x from both sides of = \n" ); document.write( "13-x = square root(x-8)square root(x-7) \n" ); document.write( "use square root rule, square root(ab) = square root(a)squar root(b) \n" ); document.write( "13-x = square root((x-8)(x+7)) \n" ); document.write( "square both sides of = \n" ); document.write( "169-26x-x^2 = (x-8)(x+7) \n" ); document.write( "169-26x-x^2 = x^2-x-56 \n" ); document.write( "-25x = -225 \n" ); document.write( "x = 9 \n" ); document.write( "answer is C\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |