document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885438>Question 885438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the number 34 and 12. At some point during the lives of you and the youngest person, your age will be three times his/her age at that moment. Write an equation which models how old in years each of you will be when you are three times as old as the younger person. \r<BR>\n" );
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document.write( "I'm having a hard timing understanding this question.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535154 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 34 + x = 3(12 +x)<BR>\n" );
document.write( "34 + x = 36 +3x<BR>\n" );
document.write( "2x = -2<BR>\n" );
document.write( "x = -1<BR>\n" );
document.write( "you will be 33 and youngest will be 11\r<BR>\n" );
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