document.write( "Question 74538: One day, the temperature at 10:00 A.M. was 41°F, and by 3:00 P.M. the temperature was 66°F. What was the hourly rate of temperature change?
\n" ); document.write( "A) 4°F/h
\n" ); document.write( "B) 5°F/h
\n" ); document.write( "C) 6°F/h
\n" ); document.write( "D) 7°F/h
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #53513 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
66-41=25 DEGREE RISE IN 5 HOURS:
\n" ); document.write( "THUS THE RATE OF CHANGE IS
\n" ); document.write( "25/5=5 DEGREE TEMPERATURE CHANGE PER HOUR.
\n" ); document.write( "
\n" );