document.write( "Question 74538: One day, the temperature at 10:00 A.M. was 41°F, and by 3:00 P.M. the temperature was 66°F. What was the hourly rate of temperature change?
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document.write( "A) 4°F/h
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document.write( "B) 5°F/h
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document.write( "C) 6°F/h
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document.write( "D) 7°F/h
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Algebra.Com's Answer #53513 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 66-41=25 DEGREE RISE IN 5 HOURS: \n" ); document.write( "THUS THE RATE OF CHANGE IS \n" ); document.write( "25/5=5 DEGREE TEMPERATURE CHANGE PER HOUR. \n" ); document.write( " |