document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885356>Question 885356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If an amount of money in P in pesos is invested at \" r \" percent compounded annually, it will grow to an amount A = P(1 + r)^2 in two years. Suppose Miss Madrigal wants her money amounting to Php 200,000 to grow Php 228, 980 in two years. At what rate must she invest her money  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535081 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = p(1+r)^2<BR>\n" );
document.write( "a = 228980<BR>\n" );
document.write( "p = 200000<BR>\n" );
document.write( "replace a and p in the equation to get:<BR>\n" );
document.write( "228980 = 200000(1+r)^2<BR>\n" );
document.write( "divide both sides by 200000 to get:<BR>\n" );
document.write( "228980/200000 = (1+r)^2<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "1.14449 = (1+r)^2<BR>\n" );
document.write( "take the square root of both sides to get:<BR>\n" );
document.write( "1.07 = 1+r<BR>\n" );
document.write( "subtract 1 from both sides to get:<BR>\n" );
document.write( "r = .07<BR>\n" );
document.write( "the rate she needs to invest her money at is 7%.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );