document.write( "Question 74506: How many liters of a 14% alcohol solution must be mixed with 20 liters of a 50% solution to get a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #53505 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .14x+.50*20=.30(x+20) \n" ); document.write( ".14x+10=.3x+6 \n" ); document.write( ".14x-.3x=6-10 \n" ); document.write( "-.16x=-4 \n" ); document.write( "x=-4/-.16 \n" ); document.write( "x=25 liters of 14% alcohol is needed to make the required mix \n" ); document.write( "proof \n" ); document.write( ".14*25+.5*20=.3(25+20) \n" ); document.write( "3.5+10=.3(45) \n" ); document.write( "13.5=13.5 \n" ); document.write( " |