document.write( "Question 884822: Convert the equation to the standard form for a hyperbola by completing the square on x and y. \r
\n" ); document.write( "\n" ); document.write( "y2 - 25x2 + 4y + 50x - 46 = 0\r
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Algebra.Com's Answer #535046 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Convert the equation to the standard form for a hyperbola by completing the square on x and y.
\n" ); document.write( "y2 - 25x2 + 4y + 50x - 46 = 0
\n" ); document.write( "\"-25x%5E2%2B50x%2By%5E2%2B4y=46\"
\n" ); document.write( "\"-+25%28x%5E2-2x%2B1%29%2B%28y%5E2%2B4y%2B4%29=46-25\"
\n" ); document.write( "\"-25%28x-1%29%5E2%2B%28y%2B2%29%5E2=21\"
\n" ); document.write( "\"%28y%2B2%29%5E2-25%28x-1%29%5E2=21\"
\n" ); document.write( "\"%28y%2B2%29%5E2%2F%2821%29-25%28x-1%29%5E2%2F%2825%2F21%29=1\"
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis and center at (1,-2)
\n" ); document.write( "Its standard form of equation: \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\"
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