document.write( "Question 885215: A circle passes through the centre of a circle X^2 + Y^2 - 3X - 4Y - 1 = 0 and it's centre is (5,2).find it's equation. \n" ); document.write( "
Algebra.Com's Answer #535029 by KMST(5328)\"\" \"About 
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For the first circle, the given equation is \"x%5E2%2By%5E2-3x-4y-1=0\" .
\n" ); document.write( "We can transform it:
\n" ); document.write( "\"x%5E2%2By%5E2-3x-4y=1\"
\n" ); document.write( "\"x%5E2-3x%2By%5E2-4y=1\"
\n" ); document.write( "\"x%5E2-3x%2B9%2F4%2By%5E2-4y%2B4=1%2B9%2F4%2B4\"
\n" ); document.write( "\"%28x-3%2F2%29%5E2%2B%28y-2%29%5E2=1%2B9%2F4%2B4\"
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\n" ); document.write( "\"x=3%2F2\" and \"y=2\" are the coordinates of the center of the circle,
\n" ); document.write( "and \"%28x-3%2F2%29%5E2%2B%28y-2%29%5E2\" is the square of the distance from a point (x,y) to that center.
\n" ); document.write( "\"1%2B9%2F4%2B4\" is the square of the radius of the circle, but I do not need to calculate it.
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\n" ); document.write( "The distance from the center of that first circle (with \"x=3%2F2\" and \"y=2\" )
\n" ); document.write( "to point (5,2) (also with \"y=2\" ) is \"abs%285-3%2F2%29=abs%287%2F2%29=7%2F2\" .
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\n" ); document.write( "A circle centered at (5,2), with radius \"R\" has the equation
\n" ); document.write( "\"%28x-5%29%5E2%2B%28y-2%29%5E2=R%5E2\"
\n" ); document.write( "If the circle passes through a point with \"x=3%2F2\" and \"y=2\" ,
\n" ); document.write( "which is at a distance \"7%2F2\" from (5,2), then \"R=7%2F2\" , and
\n" ); document.write( "\"%28x-5%29%5E2%2B%28y-2%29%5E2=%287%2F2%29%5E2\" is the equation of the second circle.
\n" ); document.write( "It can also be written as
\n" ); document.write( "\"%28x-5%29%5E2%2B%28y-2%29%5E2=49%2F4\" , or further manipulated into whatever equivalent equation you desire:
\n" ); document.write( "\"x%5E2-10x%2B25%2By%5E2-4y%2B4=49%2F4\"-->\"x%5E2%2By%5E2-10x-4y%2B25%2B4-49%2F4=0\"-->\"x%5E2%2By%5E2-10x-4y%2B67%2F4=0\"-->\"4x%5E2%2B4y%5E2-40x-16y%2B67=0\"
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