document.write( "Question 885250: Missing coordinate A(-3,2) , B(x,3) , c(4,5) if AB=BC , Find the value of x??? \n" ); document.write( "
Algebra.Com's Answer #534997 by algebrapro18(249)\"\" \"About 
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To find x we need to find the distance between A and B and the distance between B and C. We can then set the two distances equal to each other and solve for x, since AB=BC.
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\n" ); document.write( "\n" ); document.write( "So finding the distance between A and B we get:
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\n" ); document.write( "\n" ); document.write( "\"AB=sqrt%28%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29\"
\n" ); document.write( "\"AB=sqrt%28%28-3-x%29%5E2%2B%282-3%29%5E2%29\"
\n" ); document.write( "\"AB=sqrt%28x%5E2%2B6x%2B9%2B%28-1%29%5E2%29\"
\n" ); document.write( "\"AB=sqrt%28x%5E2%2B6x%2B9%2B1%29\"
\n" ); document.write( "\"AB=sqrt%28x%5E2%2B6x%2B10%29\"
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\n" ); document.write( "\n" ); document.write( "That's as simplified as that can get. So now we find the distance between B and C:
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\n" ); document.write( "\n" ); document.write( "\"BC=sqrt%28%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29\"
\n" ); document.write( "\"BC=sqrt%28%28x-4%29%5E2%2B%283-5%29%5E2%29\"
\n" ); document.write( "\"BC=sqrt%28x%5E2-8x%2B16%2B%28-2%29%5E2%29\"
\n" ); document.write( "\"BC=sqrt%28x%5E2-8x%2B16%2B4%29\"
\n" ); document.write( "\"BC=sqrt%28x%5E2-8x%2B20%29\"
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\n" ); document.write( "\n" ); document.write( "So now we can set AB = BC and solve for x.\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%5E2%2B6x%2B10%29\" = \"sqrt%28x%5E2-8x%2B20%29\" square both sides to get rid of the square root\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x%2B10+=+x%5E2-8x%2B20\" Subtract (x2-8x+20) from both sides
\n" ); document.write( "\"x%5E2-x%5E2%2B6x%2B8x%2B10-20+=+0\" combine like terms
\n" ); document.write( "\"14x-10+=+0\" add 10 to both sides
\n" ); document.write( "\"14x+=+10\" divide both sides by 14
\n" ); document.write( "x = 10/14 = 5/7
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