document.write( "Question 885185: The diameter of the rear and front wheels of a pushcart are 30 and 18 respectively. In what distance in feet would the front wheel make 20 revolutions more than rear wheels? \n" ); document.write( "
Algebra.Com's Answer #534990 by ankor@dixie-net.com(22740)\"\" \"About 
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The diameter of the rear and front wheels of a pushcart are 30 and 18 respectively.
\n" ); document.write( " In what distance in feet would the front wheel make 20 revolutions more than rear wheels?
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\n" ); document.write( "The ratio of the two circumferences is the same as the two diameters: 30:18
\n" ); document.write( "let n = no. of rev of the rear wheel
\n" ); document.write( "30n = 18(n+20)
\n" ); document.write( "30n = 18n + 360
\n" ); document.write( "30n - 18n = 360
\n" ); document.write( "n = 360/12
\n" ); document.write( "n = 30 rev for the rear wheel, to exceed the front wheel rev by 20
\n" ); document.write( ":
\n" ); document.write( "Find the distance using the circumference
\n" ); document.write( "30*pi*30 = 2827.4 inches, back wheel
\n" ); document.write( ":
\n" ); document.write( "Check this using the front wheel
\n" ); document.write( "the front wheel goes the same dist when it has 50 rev
\n" ); document.write( "50*pi*18 = 2827.4 inches
\n" ); document.write( "Find this distance in ft
\n" ); document.write( "2827.4/12 = 235.6 ft \n" ); document.write( "
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