document.write( "Question 885200: How do you solve 3cot^2-3cotx=1
\n" ); document.write( "I know you have to divide by 3 but I not sure what to do from there. \n" ); document.write( "
Algebra.Com's Answer #534986 by lwsshak3(11628)\"\" \"About 
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How do you solve
\n" ); document.write( "3cot^2-3cotx=1
\n" ); document.write( "for interval: [0,π]
\n" ); document.write( "3cotx-3cotx-1=0
\n" ); document.write( "solve for cotx using quadratic formula:
\n" ); document.write( " \"cotx+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=3, b=-3, c=-1
\n" ); document.write( "ans:
\n" ); document.write( "cotx≈-0.26
\n" ); document.write( "tanx=1/cotx=1/-0.26=-3.85
\n" ); document.write( "x=1.82 radians
\n" ); document.write( "or
\n" ); document.write( "cotx≈1.26
\n" ); document.write( "tanx=1/cotx=1/1.26=0.79
\n" ); document.write( "x=0.67 radians\r
\n" ); document.write( "\n" ); document.write( "ans rounded to 2 decimal places
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