document.write( "Question 885126: \log_(5) (x) + \log_(5) (x+5) = 9 \r
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document.write( "I need help solving for x. I keep getting crazy numbers.
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document.write( "Because I have base 5, I set up my equation as
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document.write( "5^9 = x(x+5)
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document.write( "1953125 = x^2 +5x
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document.write( "x^2 + 5x - 1953125 = 0\r
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document.write( "I couldn't factor it and the quadratic formula didnt seem to work either. Please help! Thank you \n" );
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Algebra.Com's Answer #534940 by nerdybill(7384) You can put this solution on YOUR website! log_(5) (x) + log_(5) (x+5) = 9 \n" ); document.write( "log_(5) [(x)(x+5)] = 9 \n" ); document.write( "(x)(x+5) = 5^9 \n" ); document.write( "x^2+5x = 1953125 \n" ); document.write( "x^2+5x-1953125 = 0 \n" ); document.write( "apply the \"quadratic\" formula: \n" ); document.write( "x = -b+-sqrt(b^2-4ac)/(2a) \n" ); document.write( "to get: \n" ); document.write( "x = {1395.04, -1400.04} \n" ); document.write( "throw out the negative solution (extraneous) to get \n" ); document.write( "x = 1395.04 \n" ); document.write( ". \n" ); document.write( "details of quadratic follows: \n" ); document.write( "
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