document.write( "Question 885126: \log_(5) (x) + \log_(5) (x+5) = 9 \r
\n" ); document.write( "\n" ); document.write( "I need help solving for x. I keep getting crazy numbers.
\n" ); document.write( "Because I have base 5, I set up my equation as
\n" ); document.write( "5^9 = x(x+5)
\n" ); document.write( "1953125 = x^2 +5x
\n" ); document.write( "x^2 + 5x - 1953125 = 0\r
\n" ); document.write( "\n" ); document.write( "I couldn't factor it and the quadratic formula didnt seem to work either. Please help! Thank you
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Algebra.Com's Answer #534940 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log_(5) (x) + log_(5) (x+5) = 9
\n" ); document.write( "log_(5) [(x)(x+5)] = 9
\n" ); document.write( "(x)(x+5) = 5^9
\n" ); document.write( "x^2+5x = 1953125
\n" ); document.write( "x^2+5x-1953125 = 0
\n" ); document.write( "apply the \"quadratic\" formula:
\n" ); document.write( "x = -b+-sqrt(b^2-4ac)/(2a)
\n" ); document.write( "to get:
\n" ); document.write( "x = {1395.04, -1400.04}
\n" ); document.write( "throw out the negative solution (extraneous) to get
\n" ); document.write( "x = 1395.04
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\n" ); document.write( "details of quadratic follows:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B5x%2B-1953125+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%285%29%5E2-4%2A1%2A-1953125=7812525\".
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\n" ); document.write( " Discriminant d=7812525 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-5%2B-sqrt%28+7812525+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%285%29%2Bsqrt%28+7812525+%29%29%2F2%5C1+=+1395.04472200356\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%285%29-sqrt%28+7812525+%29%29%2F2%5C1+=+-1400.04472200356\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"1x%5E2%2B5x%2B-1953125\" can be factored:
\n" ); document.write( " \"1x%5E2%2B5x%2B-1953125+=+1%28x-1395.04472200356%29%2A%28x--1400.04472200356%29\"
\n" ); document.write( " Again, the answer is: 1395.04472200356, -1400.04472200356.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B5%2Ax%2B-1953125+%29\"

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