document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885111>Question 885111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of a rectangular lot with a perimeter of 72 m if the length is 6 m more than the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534931 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w = width<BR>\n" );
document.write( "w + 6 = length {length is 6 more than width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
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document.write( "2w + 2(w + 6) = 72   {substituted width and length into perimeter formula}<BR>\n" );
document.write( "2w + 2w + 12 = 72 {used distributive property}<BR>\n" );
document.write( "4w + 12 = 72 {combined like terms}<BR>\n" );
document.write( "4w = 60 {subtracted 12 from each side}<BR>\n" );
document.write( "w = 15 {divided each side by 4}<BR>\n" );
document.write( "w + 6 = 21 {substituted 15, in for w, into w + 6}\r<BR>\n" );
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document.write( "width = 15 m<BR>\n" );
document.write( "length = 21 m<BR>\n" );
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