document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74520>Question 74520</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534419232/algebrahomeworkh>intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> hi can someone please help me. Thanks in advance.\r<BR>\n" );
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document.write( "The sum of the measures of the angeles of any triangle is 180 degress. In triangle ABC, angle A measures 100 degress less than the sum of the measures of angle B and angles C, and the measure of C is 40 degres less than the twice the measure of angeles B. Find the measure of each angle of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53489 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= the measure of angle B\r<BR>\n" );
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document.write( "Then (2x-40)=the measure of angle C<BR>\n" );
document.write( "{x+(2x-40)}=the sum of the measures of angles B and C<BR>\n" );
document.write( "So {x+(2x-40)}-100=the measure of angle A\r<BR>\n" );
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document.write( "Then our equation to solve is\r<BR>\n" );
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document.write( "A+B+C=180  or\r<BR>\n" );
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document.write( "x+(2x-40)+{x+(2x-40)}-100=180  get rid of parens and brackets\r<BR>\n" );
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document.write( "x+2x-40+x+2x-40-100=180  collect like terms<BR>\n" );
document.write( "6x-180=180  add 180 to both sides\r<BR>\n" );
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document.write( "6x=360  divide both sides by 6<BR>\n" );
document.write( "x=60 degrees---------------------------the measure of angle B\r<BR>\n" );
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document.write( "2x-40=120-40=80 degrees---------------------the measure of angle C\r<BR>\n" );
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document.write( "x+2x-40-100=180-140=40 degrees ---------------the measure of angle A\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "60+80+40=180<BR>\n" );
document.write( "180=180<BR>\n" );
document.write( "measure of C is 40 degrees less than the twice the measure of angle B.<BR>\n" );
document.write( "2*60-40=80<BR>\n" );
document.write( "80=80<BR>\n" );
document.write( "angle A measures 100 degress less than the sum of the measures of angle B and angle C<BR>\n" );
document.write( "60+80-100=40<BR>\n" );
document.write( "40=40\r<BR>\n" );
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document.write( "Hoe this helps----ptaylor\r<BR>\n" );
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