document.write( "Question 884982: John is twice as old as Peter. In 8 years, John’s age will be 2 more than the sum of their present ages.
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Algebra.Com's Answer #534828 by Edwin McCravy(20060)\"\" \"About 
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John is twice as old as Peter. In 8 years, John’s age will be 2 more than the sum of their present ages.
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document.write( "So J = 2P\r\n" );
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document.write( "In 8 years, John’s age will be J+8 \r\n" );
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document.write( "and J+8 will then be 2 more than the sum of their present ages, J+P \r\n" );
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document.write( "So\r\n" );
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document.write( "J+8 = J+P + 2\r\n" );
document.write( "  6 = P\r\n" );
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document.write( "J = 2P = 2(6) = 12\r\n" );
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document.write( "So John is 12.\r\n" );
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document.write( "Checking:\r\n" );
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document.write( "John, who is 12, is twice as old as Peter, who is 6.  That checks. \r\n" );
document.write( "In 8 years, John’s age (12+8=20) will be 2 more than the \r\n" );
document.write( "sum of their present ages (12+6=18). Since 20 is 2 more than 18,\r\n" );
document.write( "the answer is correct. \r\n" );
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document.write( "Edwin
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