document.write( "Question 884939: Need help setting this up:
\n" ); document.write( "A couple invested part of $12,000 at 6% interest, and the rest at 7.5%. If their target annual income os $810, how much money should they invest in each account? \n" ); document.write( "

Algebra.Com's Answer #534825 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = amount invested @ 6%
\n" ); document.write( " $\"+12000+-+x+\"$ = amount invested @ 7.5%
\n" ); document.write( "-------------------
\n" ); document.write( " $\"+.06x+%2B+.075%2A%28+12000+-+x+%29+=+810+\"$
\n" ); document.write( " $\"+.06x+%2B+900+-+.075x+=+810+\"$
\n" ); document.write( " $\"+-.015x+=+-90+\"$
\n" ); document.write( " $\"+x+=+6000+\"$
\n" ); document.write( " $\"+12000+-+6000+=+6000+\"$
\n" ); document.write( "-------------------------
\n" ); document.write( "They need to invest half of the $12,000
\n" ); document.write( "at each rate
\n" ); document.write( "-----------
\n" ); document.write( "check:
\n" ); document.write( " $\"+.06x+%2B+.075%2A%28+12000+-+x+%29+=+810+\"$
\n" ); document.write( " $\"+.06%2A6000+%2B+.075%2A6000+=+810+\"$
\n" ); document.write( " $\"+360+%2B+450+=+810+\"$
\n" ); document.write( " $\"+810+=+810+\"$
\n" ); document.write( "OK \n" ); document.write( "

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