document.write( "Question 884961: wendy is 6 years younger than her brother.The product of their ages is 91.Find their ages.
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Algebra.Com's Answer #534822 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+w+\"$ = Wendy's age
\n" ); document.write( "Let $\"+b+\"$ = brother's age
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\n" ); document.write( "(1) $\"+w+=+b+-+6+\"$
\n" ); document.write( "(2) $\"+w%2Ab+=+91+\"$
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\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+%28+b+-+6+%29%2Ab+=+91+\"$
\n" ); document.write( "(2) $\"+b%5E2+-+6b+=+91+\"$
\n" ); document.write( "Complete the square
\n" ); document.write( "(2) $\"+b%5E2+-+6b+%2B+%28+6%2F2+%29%5E2++=+91+%2B+%28+6%2F2+%29%5E2+\"$
\n" ); document.write( "(2) $\"+b%5E2++-+6b+%2B+9+=+91+%2B+9+\"$
\n" ); document.write( "(2) $\"+%28+b+-+3+%29%5E2+=+100+\"$
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "(2) $\"+b+-+3+=+10+\"$
\n" ); document.write( "(2) $\"+b+=+13+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+w+=+b+-+6+\"$
\n" ); document.write( "(1) $\"+w+=+13+-+6+\"$
\n" ); document.write( "(1) $\"+w+=+7+\"$
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\n" ); document.write( "Wendy is 7 and her brother is 13
\n" ); document.write( "check:
\n" ); document.write( " $\"+7%2A13+=+91+\"$
\n" ); document.write( "OK\r
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