document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884949>Question 884949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> five consecutive integers have the property that the sum of the first 4 is exactly three times the fifth. find the sum of the nest five consecutive integers.    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534804 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A + B + C + D = 3E<BR>\n" );
document.write( "B = A+1 (because the numbers are consecutive)<BR>\n" );
document.write( "C = A+2<BR>\n" );
document.write( "D = A+3<BR>\n" );
document.write( "E = A+4<BR>\n" );
document.write( "Let's find A.  Then, since everything is consecutive, we'll know the values of the others.<BR>\n" );
document.write( "Substitute the known values from the bottom equations into the top.<BR>\n" );
document.write( "A + B + C + D = 3E<BR>\n" );
document.write( "A + (A+1) + (A+2) + (A+3) = 3(A+4)<BR>\n" );
document.write( "Add / Distribute<BR>\n" );
document.write( "4A + 6 = 3A + 12<BR>\n" );
document.write( "Subtract 3A from each side<BR>\n" );
document.write( "A + 6 = 12<BR>\n" );
document.write( "Subtract 6 from each side<BR>\n" );
document.write( "A = 6<BR>\n" );
document.write( "If the first number is 6, the other numbers are 7,8,9, and 10<BR>\n" );
document.write( "Let's prove it.<BR>\n" );
document.write( "6+7+8+9 = 30<BR>\n" );
document.write( "10 * 3 = 30<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );