document.write( "Question 884928: confused.
\n" ); document.write( "Write the equation of the line in standard form which passes through (-9,3) perpendicular to x-3y=0
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Algebra.Com's Answer #534799 by josgarithmetic(39617)\"\" \"About 
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\"x-3y=0\"
\n" ); document.write( "\"x=3y\"
\n" ); document.write( "\"y=x%2F3\", the slope is \"%281%2F3%29\".\r
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\n" ); document.write( "\n" ); document.write( "The slope you want for the line perpendicular to \"x-3y=0\" must be \"-3\". The slopes for perpendicular lines in a plane must be negative reciprocals.\r
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\n" ); document.write( "\n" ); document.write( "Using SLOPE-INTERCEPT FORM, you want an equation \"y=-3x%2Bb\" and you do not yet know b. You know that the line must pass through (-9,3).
\n" ); document.write( "\"y%2B3x=b\"
\n" ); document.write( "Substitute the coordinate values.
\n" ); document.write( "\"b=3%2B3%28-9%29\"
\n" ); document.write( "\"b=3-27\"
\n" ); document.write( "\"b=-24\"
\n" ); document.write( "-
\n" ); document.write( "Equation in slope-intercept form still, is \"y=-3x-24\".
\n" ); document.write( "Convert that into standard form.
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