document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884814>Question 884814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the terms of the following arithmetic progressions.\r<BR>\n" );
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document.write( "6,0,-6,-12... To 100terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534745 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534745\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you know the first and last terms use this<BR>\n" );
document.write( "S = ½(A1 + An)n<BR>\n" );
document.write( "If you know the first term and the difference between terms use this\r<BR>\n" );
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document.write( "S = ½(2*A1 + (n-1)d)n\r<BR>\n" );
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document.write( "We don;t know the last term<BR>\n" );
document.write( "d=-6<BR>\n" );
document.write( "n=100<BR>\n" );
document.write( "A1=6\r<BR>\n" );
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document.write( "S = ½(2*(-6) + (99)*(-6))100\r<BR>\n" );
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document.write( "S = 50(-12 + (99)*(-6))\r<BR>\n" );
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document.write( "S = 50(-12-594)<BR>\n" );
document.write( "S=50*-606<BR>\n" );
document.write( "S=-30300 </SPAN>\n" );
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