document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884835>Question 884835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi, i was ask to factor this equation and i am really not sure how to do it, any help will be greatly appreciated 8^2(x^2+2)^2-2x(4x^3+1)(x^2+2). the answer is 2x(x^2+2)(8x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534730 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20060)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You must have mistyped something because when you substitute x=1 in\r<BR>\n" );
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document.write( "8^2(x^2+2)^2-2x(4x^3+1)(x^2+2)\r<BR>\n" );
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document.write( "you get\r<BR>\n" );
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document.write( "8^2(1^2+2)^2-2*1(4*1^3+1)(1^2+2) = 546\r<BR>\n" );
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document.write( "But when you substitute x=1 in\r<BR>\n" );
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document.write( "2x(x^2+2)(8x-1)\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "2*1(1^2+2)(8*1-1) = 42\r<BR>\n" );
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document.write( "Give the corrected problem in the thank-you note and we'll help you.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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