document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884865>Question 884865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cross country skier reaches the 13-km mark of a race 40 min after reaching the 3-km mark. Find the speed (average rate of change)  of the skier. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534720 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The difference between 13km and the 3km mark is 10km.<BR>\n" );
document.write( "He travels 10km in 40 minutes.<BR>\n" );
document.write( "That's 1 km per 4 minutes.<BR>\n" );
document.write( "60 minutes in an hour.<BR>\n" );
document.write( "60 * <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >=15kmh </SPAN>\n" );
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