document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884873>Question 884873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose area is 154 cm2 and whose perimeter is 50 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534719 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area = length * width<BR>\n" );
document.write( "Factors of 154 are:<BR>\n" );
document.write( "1, 2, 7, 11, 14, 22, 77, 154<BR>\n" );
document.write( "The perimeter fence is 2L + 2W.  In this case 50cm.  So L + W would be half that, or 25.<BR>\n" );
document.write( "Which factors of 154 sum to 25?<BR>\n" );
document.write( "Only 11 and 14.<BR>\n" );
document.write( "The length is 14 and the width is 11.<BR>\n" );
document.write( "The perimeter is 14+14+11+11 or 50<BR>\n" );
document.write( "The area is 14 * 11, or 154 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );