document.write( "Question 884871: Three years ago,the difference in the ages of two brothers was 2 years.The sum of their present ages will double in 10 years.What is the present age of the elder brother
\n" ); document.write( "(A)6
\n" ); document.write( "(B)11
\n" ); document.write( "(C)7
\n" ); document.write( "(D)9
\n" ); document.write( "

Algebra.Com's Answer #534717 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
The difference in their ages won't change. It's still 2 years. the \"three years ago\" is to mess up your equation :-\
\n" ); document.write( "A = B + 2
\n" ); document.write( "A+10 + B+10 = 2(A+B)
\n" ); document.write( "A + B + 20 = 2A + 2B
\n" ); document.write( "Substitute the value of A from the first equation into the second.
\n" ); document.write( "(B+2) + B + 20 = 2(B+2) + 2B
\n" ); document.write( "Add
\n" ); document.write( "2B + 22 = 2B + 4 + 2B
\n" ); document.write( "2B + 22 = 4B + 4
\n" ); document.write( "Subtract 2B from each side
\n" ); document.write( "22 = 2B + 4
\n" ); document.write( "Subtract 4 from each side
\n" ); document.write( "18 = 2B
\n" ); document.write( "Divide each side by 2
\n" ); document.write( "9 = B
\n" ); document.write( "If younger brother is 9, then older brother is 11.
\n" ); document.write( ".
\n" ); document.write( "Let's prove it.
\n" ); document.write( "\"The sum of their present ages will double in 10 years
\n" ); document.write( "9+11 = 20
\n" ); document.write( "In 10 years, 19+21=40
\n" ); document.write( "Success!
\n" ); document.write( "
\n" );