document.write( "Question 884833: A father is seven times as old as his son. In five years time he will be 4 times as old as his son. Find the product of their ages 3 years ago. \n" ); document.write( "
Algebra.Com's Answer #534696 by geetha_rama(94)\"\" \"About 
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Let x be the father's age and y be son's age
\n" ); document.write( "\"x+=+7%2Ay\" -> eq 1
\n" ); document.write( "After 5 yrs
\n" ); document.write( "\"x%2B5=4%2A%28y%2B5%29\" -> eq 2
\n" ); document.write( "Solve for x and y from equation 1 and 2\r
\n" ); document.write( "\n" ); document.write( "Once you get x and y
\n" ); document.write( "do \"%28x-3%29%2A%28y-3%29\"
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