document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884821>Question 884821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A FATHER IS 3 TIMES  AS OLD AS HIS SON. AFTER 12 YEARS HIS AGE WILL BE TWICE AS THAT OF HIS SON THEN FIND THE PRESENT AGES<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534688 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F = 3S<BR>\n" );
document.write( "F+12 = 2(S+12)<BR>\n" );
document.write( "Substitute the value of F from the first equation into the second.<BR>\n" );
document.write( "(3S) + 12 = 2S + 24<BR>\n" );
document.write( "Subtract 2S from each side<BR>\n" );
document.write( "S + 12 = 24<BR>\n" );
document.write( "Subtract 12 from each side<BR>\n" );
document.write( "S = 12<BR>\n" );
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document.write( "If the son is 12, then the father is 36.<BR>\n" );
document.write( "In 12 years, the son will be 24 and the father 48.<BR>\n" );
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