document.write( "Question 884126: When it is assembled, a flute is 29 inches long. The middle piece is 4 inches less than twice as long as the first piece. The last piece is two-thirds as long as the first piece. Find the length of each piece of the flute. \n" ); document.write( "
Algebra.Com's Answer #534686 by JulietG(1812) You can put this solution on YOUR website! A + B + C = 29 \n" ); document.write( "B = 2A-4 \n" ); document.write( "C = \n" ); document.write( "Substitute the known values of B & C into the first equation. \n" ); document.write( "A + B + C = 29 \n" ); document.write( "A + (2A-4) + \n" ); document.write( "Add \n" ); document.write( "3 \n" ); document.write( "Add 4 to each side \n" ); document.write( "3 \n" ); document.write( " \n" ); document.write( "Let's get rid of that pesky fraction; multiply each side by 3 \n" ); document.write( "11A = 99 \n" ); document.write( "Divide each side by 11 \n" ); document.write( "A = 9 \n" ); document.write( ". \n" ); document.write( "Now that we have A, we can find the other lengths. \n" ); document.write( "B is (2*9) - 4, or 18-4, or 14 \n" ); document.write( "C is \n" ); document.write( "Add them all together to prove -- 9 + 14 + 6 = 29 \n" ); document.write( "Success! \n" ); document.write( " |