document.write( "Question 884818: If a town having a population of 5000 in 1971 has a 20% increase every five years what is its expected population in the year 2001? \n" ); document.write( "
Algebra.Com's Answer #534681 by JulietG(1812)\"\" \"About 
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1971 = 5000
\n" ); document.write( "1976 = 5000 * 1.2 = 6000
\n" ); document.write( "1981 = 6000 * 1.2 = 7200
\n" ); document.write( "1986 = 7200 * 1.2 = 8640
\n" ); document.write( "1991 = 8640 * 1.2 = 10368
\n" ); document.write( "1996 = 10368 * 1.2 = 12441.6 -- but you can't have \"6%2F10\"of a person, so 12442
\n" ); document.write( "2001 = 12442 * 1.2 = 14930.4 -- same thing. No \"4%2F10\"of a person, so 14931\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "If you didn't round the 1996 data, the 2001 becomes 14929.92.
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