document.write( "Question 884793: The length of a rectangle is 5 metres shorter than three times the width. If the perimeter is 54 metres, what are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #534661 by josgarithmetic(39618) $\"\"$ $\"About$

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L for length and w for width.
\n" ); document.write( "L=-5+3w and 2w+2L=54.\r
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\n" ); document.write( "\n" ); document.write( "The perimeter equation can easily be simplified here: w+L=27.
\n" ); document.write( "The L&w relationship can be restated L-3w=-5, or 3w-L=5.\r
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\n" ); document.write( "3w-L=5
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\n" ); document.write( "w+L=27
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\n" ); document.write( "\n" ); document.write( "Ready for Elimination Method to start.
\n" ); document.write( "4w=32
\n" ); document.write( "w=8.\r
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\n" ); document.write( "\n" ); document.write( "Now return to the original equation formula for L.
\n" ); document.write( "L=-5+3w
\n" ); document.write( "L=-5+3*8
\n" ); document.write( "L=-5+24
\n" ); document.write( "L=19.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER: Length 19, width 8. \n" ); document.write( "

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