document.write( "Question 74477: Solve for x: {(3^x9^x+20)/(27^2x+5)}=81^x+5 \n" ); document.write( "
Algebra.Com's Answer #53466 by scott8148(6628)\"\" \"About 
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I have added parentheses to the equation which I think were missing:\r
\n" ); document.write( "\n" ); document.write( " (3^x*9^(x+20))/(27^(2x+5))=81^(x+5)\r
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\n" ); document.write( "\n" ); document.write( "Reduce all the numbers in the unknown terms to powers of 3 and simplify\r
\n" ); document.write( "\n" ); document.write( " or \"%283%5E%283x%2B40%29%29%2F%283%5E%286x%2B15%29%29=3%5E%284x%2B20%29\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by the denominator on the left side\r
\n" ); document.write( "\n" ); document.write( " \"3%5E%283x%2B40%29=3%5E%2810x%2B35%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since bases are the same, exponents are equal\r
\n" ); document.write( "\n" ); document.write( " \"3x%2B40=10x%2B35\" so \"x=5%2F7\"
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