document.write( "Question 884691: If one man or two women or three boys can finish a work in 66days then how many days will one man, one woman and one boy together take to finish the same work? \n" ); document.write( "

Algebra.Com's Answer #534579 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+R%5Bm%5D+\"$ = the rate that a man works
\n" ); document.write( "Let $\"+R%5Bw%5D+\"$ = the rate that a woman works
\n" ); document.write( "Let $\"+R%5Bb%5D+\"$ = the rate that a boy works
\n" ); document.write( "( the rates are in jobs / day )
\n" ); document.write( "------------------------------------
\n" ); document.write( "(1) $\"+R%5Bm%5D+=+1%2F66+\"$
\n" ); document.write( "(2) $\"+2%2AR%5Bw%5D+=+1%2F66+\"$
\n" ); document.write( "(3) $\"+3%2AR%5Bb%5D+=+1%2F66+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "(1) $\"+R%5Bm%5D+=+1%2F66+\"$
\n" ); document.write( "(2) $\"+R%5Bw%5D+=+1%2F132+\"$
\n" ); document.write( "(3) $\"+R%5Bb%5D+=+1%2F198+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "Let $\"+d+\"$ = days to finish the job
\n" ); document.write( "Add their rates of working to get
\n" ); document.write( "their rate working together
\n" ); document.write( " $\"+1%2F66+%2B+1%2F132+%2B+1%2F198+=+1%2Fd+\"$
\n" ); document.write( "Multiply both sides by $\"+66d+\"$
\n" ); document.write( " $\"+d+%2B+2d+%2B+3d+=+66+\"$
\n" ); document.write( " $\"+6d+=+66+\"$
\n" ); document.write( " $\"+d+=+11+\"$
\n" ); document.write( "One man, one woman and one boy will
\n" ); document.write( "finish the job in 11 days
\n" ); document.write( " \n" ); document.write( "

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