document.write( "Question 74456: This was on my test, I need to correct it but can't figure it out.\r
\n" ); document.write( "\n" ); document.write( "A right triangle has three consecutive integers as its sides. Set up a quadratic equation to solve the problem. Use the pythagorean theorem to find all three sides. \n" ); document.write( "

Algebra.Com's Answer #53455 by checkley75(3666) $\"\"$ $\"About$

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the three sides are x +(x+1)+(x+2)
\n" ); document.write( "x^2+(x+1)^2=(x+2)^2
\n" ); document.write( "x^2+x^2+2x+1=x^2+4x+4
\n" ); document.write( "2x^2-x^2-2x-4x+1-4=0
\n" ); document.write( "x^2-6x-3=0 using the quadratic equation we get:
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ this is the quadratic equation.
\n" ); document.write( "x=(6+-sqrt[36-4*1*-3])/2*1
\n" ); document.write( "x=(6+-sqrt[36+12])/2
\n" ); document.write( "x=(6+-sqrt48)/2
\n" ); document.write( "x=(6+-6.928)/2
\n" ); document.write( "x=(6+6.928)/2
\n" ); document.write( "x=12.928/2
\n" ); document.write( "x=6.464 is the length of the smallest side.
\n" ); document.write( "x+1=7.464 is the next longest side.
\n" ); document.write( "x+2=8.464 is the hypotenuse of this triangle. \n" ); document.write( "

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