document.write( "Question 74451: this was on my test:\r
\n" ); document.write( "\n" ); document.write( "Factor completely\r
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\n" ); document.write( "\n" ); document.write( "8x(Cubed)-27\r
\n" ); document.write( "\n" ); document.write( "in words:
\n" ); document.write( "eight x cubed minus twenty seven
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Algebra.Com's Answer #53446 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor completely:
\n" ); document.write( "\"8x%5E3-27\" Do you recognise this as the difference of two cubes?
\n" ); document.write( "\"%282x%29%5E3-%283%29%5E3\" There is a form for factoring the difference of two cubes:
\n" ); document.write( "\"A%5E3-B%5E3+=+%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\" Applying this to your case: \"A=2x\" and \"B+=+3\"
\n" ); document.write( "\"%282x%29%5E3-%283%29%5E3+=+%282x-3%29%28%282x%29%5E2%2B%282x%29%283%29%2B3%5E2%29\" Simplifying this:
\n" ); document.write( "\"8x%5E3-27+=+%282x-3%29%284x%5E2%2B6x%2B9%29\" This is it!
\n" ); document.write( "Sometimes, it is possible to factor the second set of parentheses but in this case, that's not possible.
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