document.write( "Question 884530: The table below shows a person's bank account balance for 5 years.\r
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\n" ); document.write( "\n" ); document.write( "Year
\n" ); document.write( "1998 1999 2000 2001 2002 2003 \r
\n" ); document.write( "\n" ); document.write( "Balance ($)
\n" ); document.write( "9,000.00 9,270.00 9,548.10 9,834.54 10,129.58 10,433.47 \r
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\n" ); document.write( "\n" ); document.write( " a) Find an exponential model for this data, with t = 0 corresponding to 1998\r
\n" ); document.write( "\n" ); document.write( " B(t) = \r
\n" ); document.write( "\n" ); document.write( " b) Find this person's balance in 2010 if it continues to grow at the same rate\r
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\n" ); document.write( "\n" ); document.write( " c) Estimate the year in which this person's account balance will reach $27000\r
\n" ); document.write( "\n" ); document.write( "I'm not sure where to begin this problem. I think I need it in the format B(t)= x^t but I'm not sure.
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Algebra.Com's Answer #534451 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Using EXCEL,
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\n" ); document.write( "a)\"B%28t%29=9000e%5E%280.0296t%29\"
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\n" ); document.write( "b)2010 would be year 12.
\n" ); document.write( "\"B%2811%29=9000e%5E%280.0296%2A12%29=12838.19\"
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\n" ); document.write( "c) \"9000e%5E%280.0296t%29=27000\"
\n" ); document.write( "\"e%5E%280.0296t%29=3\"
\n" ); document.write( "\"0.0296t=ln%283%29\"
\n" ); document.write( "\"t=ln%283%29%2F0.0296\"
\n" ); document.write( "\"t=37\" years
\n" ); document.write( "That would be 2035.
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