document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884564>Question 884564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is now 3 times as old as the daughter. twelve years ago she was six times as old as her daughter, how old is the daughter and mother </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534417 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> M = 3D<BR>\n" );
document.write( "M-12 = 6(D-12)<BR>\n" );
document.write( "Substitute the value of M from the first equation into the second.<BR>\n" );
document.write( "(3d-12) = 6(D-12)<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "3D-12 = 6D-72<BR>\n" );
document.write( "Subtract 3D from each side<BR>\n" );
document.write( "-12 = 3D-72<BR>\n" );
document.write( "Add 72 to each side<BR>\n" );
document.write( "60 = 3D<BR>\n" );
document.write( "Divide each side by 3<BR>\n" );
document.write( "20 = D<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If the daughter is 20, then the mother is 60.<BR>\n" );
document.write( "Twelve years ago, the daughter would have been 8 and the mother would have been 48. </SPAN>\n" );
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