document.write( "Question 884541: I have 2 candles with equal lengths. Both candles are lit at the same time. Candle A burns out at 4 hours. Candle B burns out at 3 hours. At what time is the slower burning candle twice as long as the faster burning candle? \n" ); document.write( "

Algebra.Com's Answer #534409 by skartikey(21) $\"\"$ $\"About$

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let length of both candles are 1. After t hours, length remaining of first candle would be 1-t/4 and length remaining of second candle would be 1-t/3. According to the problem:
\n" ); document.write( "2(1-t/3)=1-t/4
\n" ); document.write( "=>2-2t/3=1-t/4
\n" ); document.write( "=>1=5t/12
\n" ); document.write( "t=2.4 hours \n" ); document.write( "

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