document.write( "Question 884457: The length of a rectangle is 6 ft. longer than twice the width. If the perimeter is 90 ft. find the length and width of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #534354 by MathTherapy(10552) $\"\"$ $\"About$

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The length of a rectangle is 6 ft. longer than twice the width. If the perimeter is 90 ft. find the length and width of the rectangle.
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document.write( "Let width be W, and length, L
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document.write( "Then L = 2W + 6 ------- eq (i)
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document.write( "Since perimeter = 2L + 2W, then 2L + 2W = 90
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document.write( "2(L + W) = 2(45) ------ Factoring out GCF, 2
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document.write( "L + W = 45 ------------ eq (ii)
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document.write( "2W + 6 + W = 45 ------- Substituting  2W + 6 for L in eq (ii)
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document.write( "3W = 39
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document.write( "W, or width = , or  ft
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document.write( "Use this info to determine the value of L, or the length.
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document.write( "Then do a check!! \r
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