document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884265>Question 884265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the dimension of a rectangular field are 50 m by 40 m. A flower bed is prepared inside this field leaving a graval path of uniform all around the flower bed. The total cost of laying the flower bed and gravelling the path at rupees 30 and rupees 20 per square meter respectively is rupees 52000. find the widht of gravel path </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534248 by </B><A HREF=/tutors/aboutme.mpl?userid=geetha_rama><B>geetha_rama(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=geetha_rama><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the width of gravel path. <BR>\n" );
document.write( "Area of flower bed = (50-x)*(40-x) = x ^2 - 90x + 2000<BR>\n" );
document.write( "Area of gravel path = total area - area of flowerbed<BR>\n" );
document.write( "= 2000 - (x^2 -90x + 2000) = 90x -x^2<BR>\n" );
document.write( "Cost of laying flower bed and gravel path is 52000<BR>\n" );
document.write( "Flower bed cost = (x^2 - 90x + 2000)×30<BR>\n" );
document.write( "Gravel path cost =( 90x - x^2)*20<BR>\n" );
document.write( "(x^2-90x+2000)×30+(90x-x^2)×20=52000<BR>\n" );
document.write( "x^2 (30-20)-90x (30-20)+60000=52000<BR>\n" );
document.write( "10x^2-900x+8000=0<BR>\n" );
document.write( "x^2-90x+800=0<BR>\n" );
document.write( "x^2-10x-80x+800=0<BR>\n" );
document.write( "x=10, 80<BR>\n" );
document.write( "Width of the gravel path is 10m<BR>\n" );
document.write( " </SPAN>\n" );
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