document.write( "Question 74405This question is from textbook introduction and intermediate algebra
\n" ); document.write( ": you have 80 yards of fencing to enclose a rectangular region. find the dimensions of the rectangle that maximize the enclosed area. what is the maximum area? \n" ); document.write( "
Algebra.Com's Answer #53421 by Cintchr(481)\"\" \"About 
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With any problem like thes there are Maximums and Minimums ... and when talking fencing we have to look at Perimeter first.\r
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\n" ); document.write( "\n" ); document.write( "P1 = 1 + 1 + 39 + 39 = 80 The Area is 1 * 39 = 39
\n" ); document.write( "P2 = 2 + 2 + 38 + 38 = 80 The Area is 2 * 38 = 76
\n" ); document.write( "P3 = 3 + 3 + 37 + 37 = 80 The Area is 3 * 37 = 111
\n" ); document.write( "P4 = 4 + 4 + 36 + 36 = 80 The area is 4 * 36 = 144
\n" ); document.write( "etc .....\r
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\n" ); document.write( "\n" ); document.write( "Notice how the area gets larger as the shape moves from a rectangle to a square. A square will maximize the area that fencing can enclose. With a length of 80 ft, our dimentions are 20 by 20.\r
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\n" ); document.write( "\n" ); document.write( "P20 = 20 + 20 + 20 + 20 = 80 The Area is 20 * 20 = 400\r
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