document.write( "Question 884311: A 12 litre solution is 331/3% acid. How much water should be added to get the solution 20% acid? \n" ); document.write( "

Algebra.Com's Answer #534202 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = liters of water to be added
\n" ); document.write( " $\"+12%2A.333+=+4+\"$ liters of acid
\n" ); document.write( " in 33 1/3 % solution
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\n" ); document.write( " $\"+4+%2F+%28+x+%2B+12+%29+=+.2+\"$
\n" ); document.write( " $\"+4+=+.2%2A%28+x+%2B+12+%29+\"$
\n" ); document.write( " $\"+4+=+.2x+%2B+2.4+\"$
\n" ); document.write( " $\"+.2x+=+1.6+\"$
\n" ); document.write( " $\"+x+=+8+\"$
\n" ); document.write( "8 liters of water need to be added\r
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