document.write( "Question 884327: The sum of 2 numbers is 64. One number is 5 less than twice the other. Find the larger number \n" ); document.write( "
Algebra.Com's Answer #534198 by DrBeeee(684)\"\" \"About 
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Let x = one of the numbers
\n" ); document.write( "Let y = the other number
\n" ); document.write( "Given:
\n" ); document.write( "(1) x + y = 64 and
\n" ); document.write( "(2) x = 2y - 5
\n" ); document.write( "Put x of (2) into (1) and get
\n" ); document.write( "(3) 2y - 5 + y = 64 or
\n" ); document.write( "(4) 3y = 64 + 5 or
\n" ); document.write( "(5) 3y = 69 or
\n" ); document.write( "(6) y = 23
\n" ); document.write( "Using (2) we get
\n" ); document.write( "(7) x = 2*23 - 5 or
\n" ); document.write( "(8) x = 41
\n" ); document.write( "Check using (1).
\n" ); document.write( "Is (x+y = 64)?
\n" ); document.write( "Is (41 + 23 = 64)?
\n" ); document.write( "Is (64 = 64)? Yes
\n" ); document.write( "Answer: The two numbers are 23 and 41. \n" ); document.write( "
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