document.write( "Question 884344: solve using square root property (x-3)^2=81 \n" ); document.write( "
Algebra.Com's Answer #534197 by DrBeeee(684)\"\" \"About 
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Given:
\n" ); document.write( "(1) (x-3)^2 = 81
\n" ); document.write( "Take the square root of both sides of (1), equating the positive root (principal root) of the left side to the +/- root of the right side to get
\n" ); document.write( "(2) x - 3 = +/- sqrt(81) or
\n" ); document.write( "(3) x - 3 = +/- 9 or
\n" ); document.write( "(4) x = 3 +/- 9 or
\n" ); document.write( "(5) x = {12,-6}
\n" ); document.write( "Check the answers using (1).
\n" ); document.write( "Is ((12-3)^2 = 81)?
\n" ); document.write( "Is ((9)^2 = 81)?
\n" ); document.write( "Is (81 = 81)? Yes
\n" ); document.write( "Is ((-6-3)^2 = 81)?
\n" ); document.write( "Is ((-9)^2 = 81)?
\n" ); document.write( "Is (81 = 81)? Yes
\n" ); document.write( "Answer: x = {-6,12}\r
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