document.write( "Question 74409: Dear sir.
\n" ); document.write( " My homework is quite hard for me so if you can help me i will be very grateful....
\n" ); document.write( "I have got to find the pairs e.g 4 times b = 4b but what is 2(x-1) and 4 times ( x-1)
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Algebra.Com's Answer #53417 by bucky(2189)\"\" \"About 
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2(x - 1) and 4 times (x - 1)
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\n" ); document.write( "First, 2(x - 1)
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\n" ); document.write( "The lack of a math symbol (+,-,/,*) between the 2 and the parentheses is understood to
\n" ); document.write( "mean that this is understood to be multiplication. Then 2(x-1) means that you should multiply
\n" ); document.write( "2 times both of the terms inside the parentheses.
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\n" ); document.write( "So 2(x - 1) means to multiply 2 times x to get 2x and then multiply 2 times -1 to get -2.
\n" ); document.write( "The answer is that the pairs you are looking for are 2x - 1. This process is called
\n" ); document.write( "distributed or distributive multiplication.
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\n" ); document.write( "The same thing is done for your second problem 4 times (x - 1). Multiply the 4 times x to
\n" ); document.write( "get 4x and next multiply the 4 times -1 to get -4. So the answer to this problem is
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\n" ); document.write( "Sometimes the problem may have even more terms in the parentheses. For example:
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\n" ); document.write( "8(a + b - c)
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\n" ); document.write( "Just multiply 8 times each of the terms in parentheses to get the answer as:
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\n" ); document.write( "8a + 8b - 8c
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\n" ); document.write( "Now let's try something a little different that might help you see what is happening.
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\n" ); document.write( "Suppose you were given the problem:
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\n" ); document.write( "3(1 + 2 + 4)
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\n" ); document.write( "You could work this problem several ways. You could work it by multiplying each of the terms
\n" ); document.write( "in the parentheses by 3 to get (3*1) + (3*2) + (3*4) and after each of these three
\n" ); document.write( "multiplications are done you get 3 + 6 + 12. When you add these up you get 21.
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\n" ); document.write( "Or another way to do the problem 3(1 + 2 + 4) would be first to add the numbers in the
\n" ); document.write( "parentheses and then multiply by 3. When you add 1 + 2 + 4 you get 7 and the problem is
\n" ); document.write( "then 3(1 + 2 + 4) = 3*(7) = 21. The same answer as before. So either way results in
\n" ); document.write( "the same answer.
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\n" ); document.write( "Hope this helps you understand how to do these multiplication problems.
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