document.write( "Question 884303: John has 27 coins totaling $5.70. If he only has dimes and quarters, how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #534166 by josmiceli(19441) You can put this solution on YOUR website! (a) He can't have an odd number of quarters, \n" ); document.write( "since that would make the total look like @@.@5 \n" ); document.write( "------------------------------------------ \n" ); document.write( "(b) He can't have 23 or more quarters, since \n" ); document.write( "that is $5.75 or greater \n" ); document.write( "----------------------- \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "-------------------------------- \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "and subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( "-------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and, since \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "He has 7 dimes and 20 quarters \n" ); document.write( "check: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |