document.write( "Question 74388: Any help here I am the worst with math problems.\r
\n" ); document.write( "\n" ); document.write( "Find the product of (x2 - 3x + 5) with the quotient of (18x6 - 27x5 - 9x3) ÷ 9x3.
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Algebra.Com's Answer #53413 by bucky(2189)\"\" \"About 
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Find the product of (x^2 - 3x + 5) with the quotient of (18x^6 - 27x^5 - 9x^3) ÷ 9x^3.
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\n" ); document.write( "First we'll work on finding the quotient of:
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\n" ); document.write( "\"%2818x%5E6+-+27x%5E5+-+9x%5E3%29%2F+9x%5E3\"
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\n" ); document.write( "You do that by dividing the denominator into each of the terms in the numerator, so your
\n" ); document.write( "answer has three terms. And the way you do the division is you divide the 9 into the number
\n" ); document.write( "in the term and you also subtract the exponents on their exponents of x. So to divide
\n" ); document.write( "\"9x%5E3\" into \"18x%5E6\" you divide the 9 into the 18 to get 2, and then you subtract
\n" ); document.write( "the exponents of the x terms to get as the x part of the answer \"x%5E%286-3%29+=+x%5E3\".
\n" ); document.write( "Putting this together results in the division of the first term by the denominator
\n" ); document.write( "being \"2x%5E3\"
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\n" ); document.write( "We use the same process to divide \"-27x%5E5\" by \"9x%5E3\". Divide the 9 into the -27 and
\n" ); document.write( "get -3. Then divide the \"x%5E3\" into the \"x%5E5\" and get \"x%5E%285-3%29+=+x%5E2\".
\n" ); document.write( "Put these two divisions together and the answer for the second term is \"-3x%5E2\".
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\n" ); document.write( "And finally, divide the \"9x%5E3\" into the third term \"-9x%5E3\". The 9 into the -9 results
\n" ); document.write( "in -1 and the \"x%5E3\" into the \"x%5E3\" results in \"x%5E%283-3%29+=+x%5E0\" and by definition
\n" ); document.write( "anything raised to the 0 power is 1. So the answer for this division is -1 times 1 or
\n" ); document.write( "just -1.
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\n" ); document.write( "Putting all three terms together, the quotient is \"2x%5E3+-3x%5E2+-1\". Halfway home to being
\n" ); document.write( "done.
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\n" ); document.write( "Next the problem requires that this quotient be multiplied by \"x%5E2+-+3x+%2B+5\"
\n" ); document.write( "You can do
\n" ); document.write( "this by picking one term in the quotient and multiplying it by all the terms in \"x%5E2+-+3x+%2B+5\".
\n" ); document.write( "You will get 3 answers. Then you pick a second term from the quotient and multiply it
\n" ); document.write( "by all three terms in \"x%5E2+-+3x+%2B+5\" to get 3 more answers. Finally, you take the final
\n" ); document.write( "term in the quotient and multiply it by all three terms in \"x%5E2+-+3x+%2B+5\" to get the final
\n" ); document.write( "group of 3 answers. Then you add all 9 answers together, look for common terms that can be
\n" ); document.write( "combined, combine them and what you end up with is the answer to the problem.
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\n" ); document.write( "Before we begin this process, let's establish the multiplication ground rules. Just the opposite
\n" ); document.write( "of the division process. This time we multiply the numbers, not divide them. And we add
\n" ); document.write( "the exponents, not subtract them.
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\n" ); document.write( "OK, let's go. From the quotient let's first take the term \"2x%5E3\" and we'll multiply it
\n" ); document.write( "by all the terms in \"x%5E2+-+3x+%2B+5\". The first multiplication is of \"2x%5E3\" times
\n" ); document.write( "\"1x%5E2\" and the answer is \"2%2A1\" times \"x%5E%283%2B2%29+=+x%5E5\" to give us \"2x%5E5\".
\n" ); document.write( "The next multiplication is \"2x%5E3\" times \"-3x\" and its answer is \"2%2A%28-3%29\"
\n" ); document.write( "and \"x%5E%283%2B1%29+=+x%5E4\" which gives us a total result of \"-6x%5E4\". And finally we
\n" ); document.write( "multiply \"2x%5E3\" times \"%2B5\" which results in \"2%2A5\" and \"x%5E%283%2B0%29+=+x%5E3\" for
\n" ); document.write( "an answer of \"10x%5E3\". We now have the first 3 of the 9 multiplication answers and
\n" ); document.write( "they are \"2x%5E5+-+6x%5E4+%2B10x%5E3\".
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\n" ); document.write( "Next we take the second term from the quotient. It is \"-3x%5E2\" and we multiply it
\n" ); document.write( "by all three terms in \"x%5E2+-+3x+%2B+5\". Maybe by now you have enough of the idea to see
\n" ); document.write( "that the three answers are \"-3x%5E4+%2B+9x%5E3+-15x%5E2\". (Multiply the coefficients and add the
\n" ); document.write( "exponents for each term.)
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\n" ); document.write( "Finally multiply the last term of the quotient \"-1\" and multiply it by each term in
\n" ); document.write( "\"x%5E2+-+3x+%2B+5\" and you get \"-x%5E2+%2B+3x+-+5\" for these 3 answers.
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\n" ); document.write( "So in one long string the answers are:
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\n" ); document.write( "\"2x%5E5+-+6x%5E4+%2B+10x%5E3+-+3x%5E4+%2B+9x%5E3+-+15x%5E2+-+x%5E2+%2B+3x+-5\"
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\n" ); document.write( "You have 2 terms containing \"x%5E4\". They are \"-6x%5E4\" and \"-3x%5E4\". Combine them
\n" ); document.write( "into \"-9x%5E4\". You also can combine the \"x%5E3\" terms. \"%2B10x%5E3+%2B+9x%5E3+=+19x%5E3\". And you
\n" ); document.write( "can combine the \"x%5E2\" terms. \"-15x%5E2+-x%5E2+=+-16x%5E2\". None of the other terms can
\n" ); document.write( "be combined so the resulting string of terms is:
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\n" ); document.write( "\"2x%5E5+-9x%5E4+%2B+19x%5E3+-+16x%5E2+%2B3x+-5\" and that should be the answer to this problem.
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\n" ); document.write( "It's been a long journey. I hope that this exercise has given you some insight into multiplying
\n" ); document.write( "and dividing algebraic terms and how you combine terms that have like powers of x.
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