document.write( "Question 884252: hey!
\n" ); document.write( "I am having a lot of trouble with my year 12 maths and was wondering if anyone was able to assist!
\n" ); document.write( "the problem solving question I have been given with, shows a table of variables being
\n" ); document.write( "x | 0 | 1 | 2 | 3 | 4 |
\n" ); document.write( "y | -3 | 0 | 5 | 12 | 21 |
\n" ); document.write( "for this, it then explains the first and second difference between these numbers
\n" ); document.write( "I understand this as the first difference is
\n" ); document.write( "between -3 and 5 the difference = 3 between and 0 and 5 the difference = 5, between 5 and 12 the difference = 7, and between 12 and 21 the difference = 9\r
\n" ); document.write( "\n" ); document.write( "the second difference then being the difference between these first difference numbers,
\n" ); document.write( "3 and 5 = 2
\n" ); document.write( "5 and 7 = 2
\n" ); document.write( "7 and 9 = 2
\n" ); document.write( "I also understand these are all constant.
\n" ); document.write( "so, the question has given us the rule of y=ax^2 + bx + c which I know is a general function\r
\n" ); document.write( "\n" ); document.write( "it then explains that the first row of entries is obtained by substituting the x values into the rule and said that when x = 1 you just substitute that into the equation. being -> y=a(1) + b(1) + c
\n" ); document.write( "which then simplifies into a + b + c\r
\n" ); document.write( "\n" ); document.write( "the next part then says that the second row of entries (or the first difference in the pattern) is obtained by subtracting consecutive entries in the first row\r
\n" ); document.write( "\n" ); document.write( "my first question being - what and where are the consecutive entries ?
\n" ); document.write( "my second question being that the example then substitutes to
\n" ); document.write( "4a + 2b + c - (a + b + c) = 3a + b \r
\n" ); document.write( "\n" ); document.write( "I am unsure of where these substitutions (being the 4a and 2b) have come from ? \r
\n" ); document.write( "\n" ); document.write( "sorry for the very long explanation but I would be very grateful for an answer!
\n" ); document.write( "thank you for you're time
\n" ); document.write( ":)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #534118 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
we are dealing with a quadratic sequence and we work with the y values
\n" ); document.write( "y | -3 | 0 | 5 | 12 | 21 |
\n" ); document.write( "first difference is 3 5 7 9 (subtract first y value from second y value, second y value from third y value, ....)
\n" ); document.write( "second difference is 2 2 2 2
\n" ); document.write( "since the constant is 2, we know that we have a n^2 term in the expression for the nth term in the quadratic sequence
\n" ); document.write( "again, we look at the y values
\n" ); document.write( "y | -3 | 0 | 5 | 12 | 21 |
\n" ); document.write( "nth 1 2 3 4 5
\n" ); document.write( "n^2 1 4 9 16 25
\n" ); document.write( "subtract n^2 from y values
\n" ); document.write( " -4 -4 -4 -4 -4
\n" ); document.write( "the nth term in the geometric sequence is n^2 - 4
\n" ); document.write( "we can work this from another direction, we know
\n" ); document.write( "-3 = a(1^2) +b(1) +c
\n" ); document.write( "0 = a(0^2) +b(0) +c
\n" ); document.write( "5 = a(5^2) +b(5) +c
\n" ); document.write( "or
\n" ); document.write( "-3 = a +b +c
\n" ); document.write( "0 = c
\n" ); document.write( "5 = 25a + 5b +c
\n" ); document.write( "we know c = 0
\n" ); document.write( "-3 = a +b
\n" ); document.write( "1 = 5a +b
\n" ); document.write( "this can be solved for a and b
\n" ); document.write( "a = 1, b = -4
\n" ); document.write( "y = x^2 -4x is the quadratic form
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