document.write( "Question 884252: hey!
\n" ); document.write( "I am having a lot of trouble with my year 12 maths and was wondering if anyone was able to assist!
\n" ); document.write( "the problem solving question I have been given with, shows a table of variables being
\n" ); document.write( "x | 0 | 1 | 2 | 3 | 4 |
\n" ); document.write( "y | -3 | 0 | 5 | 12 | 21 |
\n" ); document.write( "for this, it then explains the first and second difference between these numbers
\n" ); document.write( "I understand this as the first difference is
\n" ); document.write( "between -3 and 5 the difference = 3 between and 0 and 5 the difference = 5, between 5 and 12 the difference = 7, and between 12 and 21 the difference = 9\r
\n" ); document.write( "\n" ); document.write( "the second difference then being the difference between these first difference numbers,
\n" ); document.write( "3 and 5 = 2
\n" ); document.write( "5 and 7 = 2
\n" ); document.write( "7 and 9 = 2
\n" ); document.write( "I also understand these are all constant.
\n" ); document.write( "so, the question has given us the rule of y=ax^2 + bx + c which I know is a general function\r
\n" ); document.write( "\n" ); document.write( "it then explains that the first row of entries is obtained by substituting the x values into the rule and said that when x = 1 you just substitute that into the equation. being -> y=a(1) + b(1) + c
\n" ); document.write( "which then simplifies into a + b + c\r
\n" ); document.write( "\n" ); document.write( "the next part then says that the second row of entries (or the first difference in the pattern) is obtained by subtracting consecutive entries in the first row\r
\n" ); document.write( "\n" ); document.write( "my first question being - what and where are the consecutive entries ?
\n" ); document.write( "my second question being that the example then substitutes to
\n" ); document.write( "4a + 2b + c - (a + b + c) = 3a + b \r
\n" ); document.write( "\n" ); document.write( "I am unsure of where these substitutions (being the 4a and 2b) have come from ? \r
\n" ); document.write( "\n" ); document.write( "sorry for the very long explanation but I would be very grateful for an answer!
\n" ); document.write( "thank you for you're time
\n" ); document.write( ":)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #534112 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"y=ax%5E2+%2B+bx+%2B+c\"
\n" ); document.write( "When \"x=0\",\"y=-3\"
\n" ); document.write( "\"-3=a%280%29%5E2%2Bb%280%29%2Bc\"
\n" ); document.write( "\"c=-3\"
\n" ); document.write( "So now you already know \"c\"
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\n" ); document.write( "When \"x=1\",\"y=0\"
\n" ); document.write( "\"0=a%281%29%5E2%2Bb%281%29-3\"
\n" ); document.write( "1.\"a%2Bb=3\"
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\n" ); document.write( "When \"x=2\",\"y=5\"
\n" ); document.write( "\"5=a%282%29%5E2%2Bb%282%29-3\"
\n" ); document.write( "\"4a%2B2b=8\"
\n" ); document.write( "2.\"2a%2Bb=4\"
\n" ); document.write( "Now you have two equations in two unknowns and you should be able to solve.
\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( "\"2a%2Bb-a-b=4-3\"
\n" ); document.write( "\"a=1\"
\n" ); document.write( "Now back substitute to find \"b\"
\n" ); document.write( "\"1%2Bb=3\"
\n" ); document.write( "\"b=2\"
\n" ); document.write( "So now you have all three values.
\n" ); document.write( "\"highlight_green%28y=x%5E2%2B2x-3%29\"\r
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